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2x^2=2738
We move all terms to the left:
2x^2-(2738)=0
a = 2; b = 0; c = -2738;
Δ = b2-4ac
Δ = 02-4·2·(-2738)
Δ = 21904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{21904}=148$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-148}{2*2}=\frac{-148}{4} =-37 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+148}{2*2}=\frac{148}{4} =37 $
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